y^2+19y+70=0

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Solution for y^2+19y+70=0 equation: 



y^2+19y+70=0

a = 1; b = 19; c = +70;
Δ = b2-4ac
Δ = 192-4·1·70
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-9}{2*1}=\frac{-28}{2}
=-14
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+9}{2*1}=\frac{-10}{2}
=-5
$

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